Two Fuses You have two fuses, one which burns for exactly 1 hour and one which burns for exactly 2 hours. Neither fuse burns at a constant rate so, for example, the last few inches of the first fuse could take 5 minutes or 55 minutes to burn. You have as many matches as you want. With these fuses, your task is to measure a time period of exactly 45 minutes. How do you do this? | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | v Answer: Light the one hour fuse at both ends while simulataneously lighting the 2 hour fuse at one end only. Since the first fuse will be burning from both ends, it will be comsumed twice as fast and be gone in 1/2 hour. At that time 1.5 hours (90 minutes) will remain on the second fuse. So, as soon as the first fuse burns out, light the second end of the 2 hour fuse. Since it will now be comsumed twice as fast, it will now burn up in exactly 45 minutes.